Use basic physics formula and write the specific process for each problem

314124 Momentum & Impulse - Review mon . A car of mass m, traveling at speed v, stops in time : when maximum braking force is applied. braking force is independent of mass, what time would be required to stop a car of mass 2m traveling at speed v? Work an object of mass m moving on a horizontal frictionless surface hits and sticks to an object of mass M > m, which is initially at rest on the surface? (A) The collision is elastic. (B) The momentum of th smaller magnitude than the inmal momentum of the less- (C) The speed of the objects that are stuck together will be dial speed of the less (D) The direction of motion of the objects that are stuck together depends on whether the hit is a head-on collision. Explain: Two carts are held together. Cart 1 is more massive than Cart 2. As they are forced apart by a compressed spring between them, which of the following will have the same magnitude for both carts, (A) change of velocity (B) force (C) speed (D) velocity Explain: M1: 5000 kq V1: 4 kmyhr kilogram freight c ng at 4-kilometers/hour collides and couples with an 3000-kilogram freight car which is initially at rest. The approximate kilometers/hour of these two cars is: m.1= 3000kq, Vo= OKmy Work: Questions 5 and 6: can only move along a straight, level path. The graphs below show the position Three oblige objects plotted as a function of time t. 5. The magnitude of the momentum of the object is increasing in which of the cases? (A) Il only (B) Ill only (C) I and II only (D) I and Ill only Explain 6. The sum of the forces on the object is zero in which of the cases? (A) II only (B) Ill only (C) I and ll only (D) I and Ill only Explain: mass M moves without friction across a frozen pond at speed v.. Two objects 7. An empty sled of mass M moves whitea time: first an object of mass m and then an object of mass 2m. Afterward the sled moves with speed v. What would be the final speed of the sled if the objects were dropped into it in reverse order? Work: Force ( N ) 6-0008 A.A . The graph shows the force on an object of mine ject of mass M as a function of time. For the time interval 0-seconds to 4-seconds, the total change in the momentum of the object is Work two balls are on a frictionless horizontal tabletop. Ball X initially moves at 10-meters/second, a Afterfun Figure I above. It then collides elastically with identical Ball Y which is initially at rest After the collision, Ball X moves at 6-meters/second along a path at 53' t as shown in Figure II above. Which of the following diagrams best r diagrams best represents the motion of Ball Work orit reits ne 10. A 2-kilogram object initially moving with a constant velocity is su F in the direction of motion. A graph of F as a function of time t is shown. What is the increase any, in the velocity of the object during the time the force is applied? ork: PART II: Show all work for mathematical solutions: an equation, substitutions and answers with proper units. Questions requiring an explanation answer using complete sentences to receive credit. 3.0 m/'s 2.0 kg A 2.0-kilogram frictionless cart is moving at a constant speed of 3.0-meters/second to the right on a horizontal surface, as shown above, when it collides with a second cart of undetermined mass m that is initially at rest. The force F of the collision as a function of time t is shown in the ande is the instant of initial contact. As a result of the collision, th graph below, where t = 0-seconds is the instant of initial conta required a speed of 1.6-meter/second to the right. Assume that friction is ible before, during, and after the collision. * Mez: ? Voz: omis * 2 : 1-bmis collision. (a) Calculate the magnitude and direction of the velocity of the 2.0-kilogram cart after the b) Is this an elastic collision or an inelastic collision? Justify your answer. c) Calculate the mass m of the second cart. After the collision, the second cart eventually experiences a ramp, which it traverses with no frictional losses. The g sses. The graph below shows the speed v of the second cart as a function of for the next 5.0-seconds, where t = 0-seconds is now the instant at which the carts separate. Speed w ( mats ) (d) Calculate the acceleration of the cart att = 3.0-seconds. (e) Calculate the distance traveled by the second cart during the 5.0-second interval after the collision (0-seconds