Use L$\text{'}$H$$pital$\text{'}$s rule to find the limit$.$

$\underset{x-}{lim}\frac{x^8-24}{x-8}$

Apply L$\text{'}$H$$pital$\text{'}$s rule so that the $\underset{x-}{lim}\frac{x^8-24}{x-8}$ is not an indeterminate form of the type $\frac{}{}.$

$\underset{x-}{lim}\frac{x^8-24}{x-8}=\underset{x-}{lim}$

Select the correct choico below and, if necessary, fill in the answer box to complete your choice.

A$.\underset{x-}{lim}\frac{x^8-24}{x-8}=$

$($Type an exact answer in simplified form.$)$

B$.$ The limit does not exist.