Use Newton's method with initial approximation x, = -1 to find x,, the second approximation to the solution of the following equation. x + x+5=0 X 7 Need Help? Read It Watch It Master It -/1 Points] DETAILS SCALCET9 4.8.017. Use Newton's method to find all solutions of the equation correct to six decimal places. (Enter your answers as a comma-separated list.) sin(x) = x - 1 X : Need Help? Read It Submit Answer 0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET9 4.8.019. Use Newton's method to find all solutions of the equation correct to six decimal places. (Enter your answers as a comma-separated list.) 6% = 6 - x2 X X Need Help? Read ItUse Newton's method with the specified initial approximation x, to find X3, the third approximation to the solution of the given equation. (Round your answer to four decimal places.) 2x5 - 3x2 + 2 = 0, x1 = -1 X3 Need Help? Read It 1/1 Points] DETAILS PREVIOUS ANSWERS SCALCET9 4.8.007. Use Newton's method with the specified initial approximation x, to find x, the third approximation to the solution of the given equation. (Round your answer to four decimal places.) - x2 + 1 = 0, x, = 2 X3 1.5215 Need Help? Read It -/1 Points] DETAILS SCALCET9 4.8.008. Use Newton's method with the specified initial approximation x, to find x3, the third approximation to the solution of the given equation. (Round your answer to four decimal places.) x5 = x- +4, x1 =1 X 3 Need Help? Read It