Use partial fractions to find the inverse Laplace transform of the following function. 4 F(s) = - 5 - 9s Reference Click the icon to view the table of Laplace transforms. f (t ) = e-1{F(s)} eff(t)} = F(s) F(t ) = e-1{F(s)} e(f(t)} = F(s) S 2 {F(S)} = (s > 0) cos kt $2 + 12 (s > 0 ) (Type an expression using t as the variable.) k 2 (s > 0) sin kt S s+ K (s > 0) n! th S h+ 1 (s > 0) cosh kt (s > |kl) T(a + 1) ta k shl+ 1 (s > 0) sinh kt (s > [KI) e at n! (s > a) e atn s- a (s-a)+1 (s>a)