Use partial fractions to find the inverse Laplace transform of the following function. 37 - 2s F(S) = $2 + 13s+ 36 Reference Click the icon to view the table of Laplace transforms. f(t) = e-(F(s)} 2{f(t)} = F(s) f(t ) = e-1{F(s)) L(f(t)} = F(s) S 2- (F(s)} = (s > 0) cos kt - c 1 - 2+12 (s > 0) (Type an expression using t as the variable.) K (s > 0) sin kt S s 0) n! th S n+ 1 (s > 0) cosh kt 2 - K (s > |kl) T(a + 1) ta k shl+1 (s > 0) sinh kt $2 -12 (s > |k]) n! e at (s > a) e atn s - a (s - a)n+ 1 (s>a)