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Use power series to solve the initial value problem. 6. (1 + x2 )y + 2xy' -2y = 0;y(0) = 0;y'(0) =1

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Use power series to solve the initial value problem. 6. (1 + x2 )y" + 2xy' -2y = 0;y(0) = 0;y'(0) =1

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