Use the 4-step procedure below to answer the question

1. Getting Started: State the important information and summarize the problem. If possible, include a diagram. Note any assumptions you're making. 2. Devise Plan: Devise a plan of attack before diving into the solution. Break down the problem into smaller, manageable segments. Identify which physical relationships you can apply. 3. Execute Plan: Carry out your plan, explaining each step. The argument should be easy to follow. Articulate your thought process at each step (including roadblocks). Any variables should be clearly defined, and your diagrams should be labeled. 4. Evaluate Solution: Check each solution for reasonableness. There are many ways to justify your reasoning: check the symmetry of the solution, evaluate limiting or special cases, relate the solution to situations with known solutions, check units, use dimensional analysis, and/or check the order of magnitude of an answer. Note: If you got stuck in theProblem 1: A large, negativelyr charged sheet o is pictured in the figure below. A small charge q (not shown} is a distance D (not shown} directly above this sheet. The small charge q experiences the effect of the negatively charged sheet as an electric force Fel. A second equally large, positively charged sheet cs [not shown} is then placed a distance 2D ahoye the sheet in the figure, to create a parallel plate capacitor. The small charge q experiences the effect of being 'inside' this parallel plate capacitor as an electric force F22 surlaee charge density 0' Question: Compare the magnitudes of the two electric forces on the small charge q in the two cases. In other words, is the magnitude of F2; greater than, less than, or equal to the magnitude of FE;? Justify your result. Reminder: F21 is the electric force on the little charge q when it is a distance D above the sheeto. F2; is the electric force on the little charge q when it is 'inside' the parallel plate capacitor. The parallel plate capacitor is constructed oftwo equally large, equally, and oppositely charged parallel sheets o and cr. It acts in all the normal senses you learned about for a parallel plate capacitor in lecture