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Use the construction to find a DFA that is equivalent to the following NFA. ({A,B,C,D}, {a,b}, , A, {B}), where (A,a)={D} (A,b)={B} (A,)={D} (B,a)={} (B,b)={C}
Use the construction to find a DFA that is equivalent to the following NFA. ({A,B,C,D}, {a,b}, , A, {B}), where (A,a)={D} (A,b)={B} (A,)={D} (B,a)={} (B,b)={C} (C,a)={A} (C,)={A} (D,a)={C} (D,b)={A,C}
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