Use the contingency table to the right to complete parts (a) through (c) below. A B Total 60 15 75 2 15 10 25 Total 75 25 100 a. Find the expected frequency for each cell. B Total 75 25 Total 75 25 100 (Type integers or decimals.) b. Compare the observed and expected frequencies for each cell. Choose the correct answer below. O A. The observed values are always greater than the expected values. O B. The expected values are always greater than the observed values. O C. The totals for the observed and expected frequencies are the same. O D. The totals for the observed values are always greater than the totals for the expected values.c. Compute XSTAT . Is it significant at a = 0.10? First let it, be the proportion of all events of interest in A, and let it be the proportion of all events of interest in B. Determine the hypotheses. Choose the correct answer below. OB. Ho: 1 = 12 O A. HO: Ty S#2 H1 : 1 1 > 12 OD. HO: My # 12 O C. Ho: T1 2 12 H1: 1 = 12 Hy: 1 2 Calculate the test statistic. XSTAT = (Round to two decimal places as needed.) What is the p-value? p-value = (Round to three decimal places as needed.)Is this vdue sign 'rllnt at a: 0.10? C) A. Yes, because the p-value less than or equal to the alpha level. Therefore, the null hypothesis should be rejected. C) B. No, because the pualue is greater than the alpha level. Therefore, the MI hypothesis should he rejected. {3 e. No, because the pvalue is greater than the alpha level. Therefore. the MI hypothesis should not he rejected. C) l1 Yes, because the pvalue less than or equal to the alpha level. Therefore, the null hypothesis should not be rejected