Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a. p(v) = 4\\ 4v2 + 5, a=1 V - 1 lim p(v) = lim 4 \\ 4v2+ 5 V - 1 . . . ........ = 4 lim V 4v-+ 5 . . . ... . V -> by the ---Select--- = 4 lim V - 1 4v2 + 5 by the ---Select--- = 4 lim 4v2 V - 1 V - 1 + lim 5 by the ---Select--- = 41 4 lim V2 + lim 5 V - 1 V- 1 by the ---Select--- = 4V 4 . (1) + 5 by the ---Select--- Find p(1). p(1) = Thus, by the definition of continuity, p is continuous at a = 1.V ---Select--- Sum Law Difference Law Constant Multiple Law Product Law Quotient Law Power Law Root Law Direct Substitution Property