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Use the equation 1 - 2a y + + (bxxc- 2c 2 a2 p2c2 + y = 0, p = 0 x to find
Use the equation 1 - 2a y" + + (bxxc- 2c 2 a2 p2c2 + y = 0, p = 0 x to find the general solution of the given differential equation on (0, ). xy" + 2y + 4y = 0 y(x) = x1/2 [C(4x1/2) + CY(4x1/2)] y(x) = x/2[C(2x-1/2) + CY(21/2)] y(x) = x-1/2 [C(4x1/2) + CY (4x1/2)] O y(x) = x-1/2 [C (2x 1/2) + CJ_ (21/2)] y(x) = x-1/2 [C(2x1/2) + CY (2x1/2)]
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