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Use the fact that the derivative of the function g(x)= square root of x is g(x)=1/[2(square root of x)] x to find the equation of

Use the fact that the derivative of the function g(x)= square root of x is g(x)=1/[2(square root of x)]

x to find the equation of the tangent line to the graph ofg'(x) at the point x=1.

The equation of the tangent line is y=

(It wouldn't let me put in a square root symbol)

.

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