Use the following graph and table to answer the questions below Column 1 Column 2 Column 3 Column 4 Weight over block Normal. force (N) Mass over the Static friction (N) (grams) weight carrier 35 0.264 20 0.196 45 0.333 40 0.392 59 0.343 60 0.588 60 0.392 80 0.784 65 0.441 100 0.98 74 0.490 Friccion cinetica vs Fuera normal y = (0.2191)FN + 0.2698N 0.6 0.5 0.4 Frk (N) 0.3 0.2 0.1 0.2 0.4 0.6 0.8 1.2 F (N) 1. The profile or shape of the previous graph is: 2. The profile or shape of the previous graph is due to: a. that friction is directly proportional to the normal force b. that acceleration is inversely proportional to the force of friction c. that acceleration is directly proportional to the total mass d. that the normal force is directly proportional to the friction force e. none of the above and/or below 3. To overcome the force of Static Friction, and make the object move, it must move with: a. it is not possible to answer correctly b. constant acceleration c. constant friction force d. constant total mass e. constant velocity 4. What physical quantity does the slope represent