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Use the following initialisation for this question: int num, *nPtr,**nPtrPtr; num=100; nPtr=# nPtr Ptr=&nPtr; Assuming num is stored in memory address 1000, nPtr is

Use the following initialisation for this question: int num, *nPtr, **nPtrPtr; num=100; nPtr=# nPtr

Use the following initialisation for this question: int num, *nPtr,**nPtrPtr; num=100; nPtr=# nPtr Ptr=&nPtr; Assuming num is stored in memory address 1000, nPtr is stored in memory address 2000 and nPtrPtr is stored in memory address 3000, what would be the output of the following code segment? cout

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