Use the Intermediate Value Theorem to show that the given function has a zero in the interval [0, 2]. f (x) = 1 + 42 - 2 f (z Click by List on the interval [0, 2]. f (0) = Number (2) = Number By the Intermediate Value Theorem, there is a value c in 0. 2 such that f (c) = 0, since f(0) 0 and f (2) 0