Use the method of mathematical induction to prove the following statement. Assume that n is a positive integer. 5 -6 +5 - 62+5-6"+...+5-6" =6(60 -1) What is the first step in the induction proof? O A. Show that the statement is true for n = k + 1. O B. Show that the statement is true for n = 0. O C. Show that the statement is true for n = 1. O D. Show that the statement is true for n = k. Determine S1- S : 5 . 6 +5 -62+5 -6 + ...+5-6" =6(60 -1) 0=0 Is S, a true statement? O A. No O B. Yes What is the next step in the induction proof? O A. Assume the statement holds for some k, and determine whether it then holds for k + 1. O B. Assume that the statement holds for k = 1, and determine whether it then holds for k = 2. O C. Determine whether the statement holds for any number k + 1. O D. Determine whether the statement holds for some k. Carry out the next step in the proof. Assume SK: 5 . 6 + 5 - 62 + 5 -63 + ... + 5 - 6* =6 (6* - 1) is true for some natural number k. Prove Sk+1 : 5 - 6+5 - 62 +5 - 63 + ...+5-6* +5-6*+1 = 6(). (Simplify your answer. Use integers or fractions for any numbers in the expression.)Rewrite the left side of Sk + 1 - 5- 6+5 -6+5 -6"+...+5-6*+5-6*+1=+5-6*+1 (Use integers or fractions for any numbers in the expression.) Rewrite the expression on the right side of the equation in the previous step as one expression. 5 - 6 +5 -6+5 -6"+...+5- 6* +5-6*+1 = 6 (6* - 1) +5-6*+1 = (Simplify your answer. Type your answer in factored form. Use integers or fractions for any numbers in the expression.) Does the truth of S, imply the truth of Sk + 1? O Yes O No