Use the Newton-Raphson algorithm to find an approximate solution to the following. There are two roots. (Use x₀ = 4 for the smaller value and x₀ = 12 for the larger value. For best results, do not round intermediate values in your calculations. Use two repetitions. Give your answers correct to five decimal places.)

e^{6 - x} = 12 - x

I found x0=4 but I can't figure out x0=12.