Use the NT to Show that f(X) = X4 X2 3 has a zero. O The IVT cannot be applied to find a zero. O f(x) is continuous on [-'i ,1], f(1)= -3, f(1) = -3, so we can use the NT to show there is a zero in [-1 ,1] 0 f(x) is continuous on [1,2], f(1): -3, f(2) > 0, so we can use the NT to show there is a zero in [1,2] 0 f(x) is continuous on [-2,0], f(2) > 0 , f(0) = -3, so we can not use the NT to show there is a zero, between [-20]. Use the IVT to show that f (x) = sin has a zero. X O You can use the I VI to show there is a zero in [-1, 1]. O You can use the I V I to show there is a zero in [-1, 2]. O The IV I cannot be applied to find a zero anywhere. You can use the I V I to show that there is a zero in [0.25, 1]A swimmer dives into a pool and swims to the other side. Can you use the NT (with the interval being at the start and finish) to show that the swimmer must have entered the water? 0 yes Ono