Use the probability distribution to complete parts (a) and (b) below.The number of defects per 1000 machine parts inspected

Defects	0	1	2	3	4	5
Probability	0.267	0.295	0.243	0.138	0.045	0.012

Find the mean, variance, and standard deviation of the probability distribution.

The mean is

enter your response here.

(Round to one decimal place as needed.)

Part 2The variance is

enter your response here.

(Round to one decimal place as needed.)

Part 3- The standard deviation is

enter your response here.

(Round to one decimal place as needed.)

Part 4(b) Interpret the results. The mean is

enter your response here,

so the average batch of 1000 machine parts has

at least 2 defects.

1 or 2 defects.

no defects.

The standard deviation is

enter your response here,

so the typical number of defects in a batch of 1000

deviates from the mean by more than 2 defects.

does not deviate from the mean.

deviates from the mean by about 1 defect.

deviates from the mean by about 2 defects.

(Round to one decimal place as needed.)