Use the provided page table to answer the following questions. Page size = 32 Number of pages = 8 Page number 0 1 2 3 4 Frame number 3 4 7 1 2 5. The number of bits needed for the logical address are: A) 12 B) 9 C) 3 D) 8 6. The number of bits represents the page displacement (offset) is A) 5 bits B) 3 bits C) 32 bits D) 8 bit 7. If we have a logical address with a page number 4 and page offset 12, then the physical address is: A) 2 B) 14 C) 76 D) 64 8. The frame size equals: A) 8 bytes B) 5 bytes C) 32 bytes D) 46 bytes 9. If the physical address space = 1024 bytes, how many frames does it has? A) 8 frames B) 10 frames C) 32 frames_D) 46 frames 10. If the memory has 32 frames then the physical space size A) 1 Kbytes B) 1 Mbytes C) 32 bytes D) 46 bytes