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he $p{K}_a$ of a solution is defined by the equation:

$p{K}_a=-log[K_a]$

here $K_a$ is the acid dissociation constant.

a$.$ Using the rules for logarithms and exponents, choose a correct solution for $K_a$ in terms of $p{K}_a.$

$K_a=log(-p{K}_a)$

$K_a={10}^{p{K}_a}$

$K_a=e^{-p{K}_a}$

$K_a=e^{p{K}_a}$

$K_a={10}^{-p{K}_a}$

b$.$ Determine the $K_a$ value if

$p{K}_a=5\mathrm{.}72$

$K_a=$