Use the Squeeze Theorem to show that lim (x2 cos(971x)) = 0. Illustrate by graphing the functions f(x) = -x2, g(x) = x2 cos(9RX), and h(x) = x2 on the same screen. Let f(x) = -x2, g(x) = x2 cos(9nix), and h(x) = x2. Then ? v s cos(91x) s|? v = ? v s x2 cos(9ntx) |? v . Since lim f(x) = lim h(x) = by the Squeeze Theorem we have lim g(x) =f( x ) = x2 + 1 if x 2 (a) Evaluate each of the following, if it exists. (If an answer does not exist, enter DNE.) (i) lim g(x) x-1 (ii) lim g(x) x - 1 (iii) g(1 ) (iv) lim g(x) x - 2 (v) lim g(x) x- 2+ (vi) lim g(x) x - 2