Use the t-distribution to find a confidence interval for a mean / given the relevant sample results. Give the best point estimate for , the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed. A 90% confidence interval for / using the sample results * = 129.4, s = 52.3, and n = 50 Round your answer for the point estimate to one decimal place, and your answers for the margin of error and the confidence interval to two decimal places. point estimate = i 129.4 margin of error = i The 90% confidence interval is i to