Using a 1184 calculator; nd the area under the standard normal curve to the left of the following z-values. Round [\"3 the answers to four decimal places. : The area to the left of z= 1.98 is D. The area to the left of z=2.32 is D. The area to the left of 2: 0.23 is D. The area to the left ofz= 1.45 is D. Use the TI-84 calculator to find the z-score for which the area to its right is 0.41. Round the answer to two decimal places. The z-score for the given area is E]. Using the 11-84 calculator; nd the area under the standard normal curve that lies between the following z-values. Round the answers to four decimal places. 0:\" (a) Find the area under the standard normal curve that lies between 2: 1.71 and 2: 1.25. (b) Find the area under the standard normal curve that lies between 2: -0.29 and Z: 0.12. (c) Find the area under the standard normal curve that lies between 2 =1.56 and Z: 1.98. (d) Find the area under the standard normal curve that lies between 2: 2.17 and z=0.07. The area between z= 1.71 and z= 1.25 is E]. The area between 2: 0.29 and 2: 0.12 is D. The area between 2 = 1.56 and z= 1.98 is D . The area between z= 2.17 and z=0.07 is D. Question 5 of 19 (1 point) | Attempt 1 OH | G) 3h 29m Remaining 6.1 Section Exercise 39, 40 (Dale) Use the TI84 calculator to find the z-score for which the area to its left is 0.78. Round the answer to two decimal places. u The z-score for the given area is E]. A normal population has mean p=7 and standard deviation 0'=5. (a) What proportion of the population is less than 18? (b) What is the probability that a randomly chosen value will be greater than 6? Round the answers to four decimal places. The proportion of the population less than 18 is I]. The probability that a randomly chosen value will be greater than 6 is El