Using an enthalpy cycle, estimate rH for the decomposition of K2O2 to K2O. The size of the ions are as follows, O is 140 pm,K is 138pm, and O22 is 167pm.xH=845kJmol1 Ulatt=r++rkvz+Z For the Kapustinskii equation for K2O2 : k=v=z+=z= pmkJmol1 Hlatt(K2O)=kkmol1Hlatt(K2O2)= The enthalpy of decomposition. ArH for the decomposition of K2O2 to K2O= kjmol1