USING C

Simple heat transfer via conduction can be determined by the formula H kA(T2- Ti)/X where: H- rate of heat transfer in watts k-coefficient of thermal conductivity for the substance A- cross sectional area in m2 T2 and Ti temperature in kelvin on the two sides of the conductor X thickness of the conductor in m For the project you will write a program that consists of a series of functions that allow the user to find an unknown value given the other values. In other words, A could be determined given H,k,T2,Ti and X. Likewise T2 can be found given H,k,A,Tiand X. The thermal conductivities will be stored in an array, and the user prompted for which one they wish. The following substances will be presented as options Substance 205 0.75 109 58 Aluminunm Asphalt Brass Cast iron Concrete Fiberglass Glass Lead Neoprene Plywood 0.04 0.8 35 0.05 0.13 429 116 inc There will be two milestones to this project. This lets me check that you are on the right track before the final hand in. Be sure that your program is properly documented and commented, poor or non-existent comments will affect your grade. I am not requiring error checking for incorrectly entered values but be sure the program works for all legitimate values. The requirements will be as follows Milestone 1: You will hand in - Algorithm Complete list of inputs and outputs Printout of the program skeleton (preprocessor directives, variable declarations, main and return, and function prototypes Milestone 2: You will hand in: Program printout showing the coded functions that were prototyped earlier Sample input and output: What substance do you wish to use? 1) Aluminum 2) Asphalt 3) Brass 4) Cast iron 5) Concrete 6) Fiberglass 6) Glass 7) Lead 8) Neoprene 9) Plywood 10) Silver 11) Zinc Enter the values (enter -99 for the unknown): Rate of heat transfer (watts): 755.0 Cross sectional area of conductor2): 0.12 Temperature on one side (kelvin): 298 Temperature on the other side: -99 Thickness of conductor (m) :0.003 Results for kA(T2 T) H = 755.0 W k-0.8 W/m-K A 0.120 m*2 T2= 298 K T1 = 274 K X= 0.003 m