Using calculus, it can be shown that if a ball is thrown upward with an initial velocity of 16 ft/s from the top of a building 124 ft high, then its height h above the ground & seconds later will be 4 h = 124 + 16t - 1612. During what time interval (in seconds) will the ball be at least 28 ft above the ground? (Enter your answer using interval notation.) Your answer cannot be understood or graded. More Information X Need Help? Read It Watch It