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Using Legender's Duplication Formula -2m 2 F(2m+1) [(k) = [(m+1) ((m+12) Or by using h n x n [ [(x+k) 2TT [ (1x) =
Using Legender's Duplication Formula -2m 2 F(2m+1) [(k) = [(m+1) ((m+12) Or by using h n x n [ [(x+k) 2TT [ (1x) = 277 where n=4, n = m+ K=0 I Convert the following formula How can E = 3 W Z 3=0 into hypergeometric form (ie a)?
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Introduction to graph theory
Authors: Douglas B. West
2nd edition
131437372, 978-0131437371
