USING MATH LAB

The maximum distance s and the maximum height h that a projectile shot at an angle theta are given by: s = v^2 0/g sin 2 theta and h = v_0^2 sin^2 theta/2g where v_0 is the shooting velocity and g = 9.81 m/s^2. Determine s(theta) and h(theta) for the following theta = 15 degree, 25 degree, 35 degree, 45 degree, 55 degree, 65 degree, 75 degree if v_0 = 260 m/s