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Using the method of substitution, 1= 2V62 + 5dz = [f(u) du where u= du = dx a = b = and f(u) = The
Using the method of substitution, 1= 2V62 + 5dz = [f(u) du where u= du = dx a = b = and f(u) = The value of the original integral is I =Estimate I = + 1 ) dx using n = 4 subintervals and 3 (a) Left endpoints. (b) Right endpoints.24 Estimate I = (-9x + 5x )do using midpoints and n = 3 subintervals.Estimate I = (3x3 + 2x + 4) da using n = 3 subintervals, and (a) Left endpoints. (b) Right endpoints.Using the method of substitution, I = \\( x(2+ 2x2)2dx = / f(u)du where U = du = f(u) = Using the above information: x' (2 + 2x2)?da = ( f(u)du (in terms of u) (in terms of x) Note: Don't forget the constant of integration in the last two blanks
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