v Part C - An object's initial velocity is 1.8 m/s in the +x direction. It slows down with a constant acceleration whose magnitude is 1.33 m/s2 .After it reaches a momentary stop it reverses its direction of motion, to the x, and speeds up with the same magnitude of the acceleration. What is its displacement (in meters) from the initial moment to t = 5.00 s '? Keep 3 digits after the decimal point. D View Available Hint(s) IWiAwoo-v displacement A0: 12.983 l m Previous Answers MuestAnswer / X Incorrect; Try Again; One attempt remaining t v Part D - At t1 = 5.0 s an object's velocity is '01 = 8.450 m/s , and at t2 = 12.0 5 its velocity is 1); = 17.760 m/s .Assuming a constant acceleration, What is its displacement (in meters) from t1 to t2? Keep 3 digits after the decimal point. ) View Available Hint(s) .Am-no? displacement A9: = l m v Part E - At t1 = 5.0 s an object's velocity is '01 = 8.450 m/s to the EAST, and at t2 = 12.0 3 its velocity is 122 = 17.760 m/s to the WEST. Assuming a constant acceleration, Take EAST as the positive direction. What is its acceleration with a proper sign? Keep 3 digits after the decimal point. A cat walks along a plank with mass M : 6.00 kg. The total length of the plank is L = 9.00 m .The plank is supported by two sawhorses. The center of mass of the plank is a distance d1 : 0.850 m to the left of sawhorse B. The cat has a mass of 3.7 kg. What is the 412 when the plank begins to tlp? When the plank tips, the normal force on the left support A, FA = 0 . v PartA - FInd d2 Keep 2 digits after the decimal point, in meters. Quest Answer V Part B - What is the distance between the cat and the RIGHT End of the plank? Keep 2 digits after the decimal point, in meters. From Cat to RIGHT End of the plank distance = 1 m muest Answer Provide Feedback