~ v s The initial velocity of a 1.39 kg block sliding down a frictionless inclined plane is found to be 1.26 m/s. Then 1.78 s later, it has a velocity of 6.88 m/s. What is the angle of the plane with respect to the horizontal? - - ~ e - - - Mass m; = 13.1 kg is on a horizontal surface. Mass m; = 7.08 kg hangs freely on a rope which is attached to the first mass. The coefficient of static friction between m; and the horizontal surface is ug = 0.484, while the coefficient of kinetic friction is py = 0.175. my A If the system is in motion with m; moving to the left, then what will be the magnitude of the system's acceleration? Consider the pulley to be massless and frictionless. A section of a high speed test track is circular with a radius of curvature R = 1620 m. TOP VIEW SIDE VIEW At what angle of @ should the track be inclined so that a car traveling at 75.0 m/s (168 mph) would keep moving in a circle if there is oil on that section of the track, i.e., it would not slip sideways even with zero friction on that section. (Hint: The car's vertical acceleration is zero.) Submit Answer | Incorrect. Tries 5/20 Previous Tries * block m, will moving Right PODOF weight of my = mag = 17.08 ) ( 9.8 ) = 69.384 N maximum limiting friction = Is = us ( mig ) = ( 0 . 4 8 4 ) ( 13 . 1 x 9.8 ) = 62. 14N so we can see that weight of my is more than limiting friction so system will not at rest. it will moving with some acceleration in Right Side a = 2. 32 4 80 / 52