V1. A random sample of 100 students is taken from a larger population of students in a multi-lecture course and the sample mean (average) of their final grades is found to be 62.25. Suppose it is known that the population standard deviation is 3.2. You wish to create a 92% confidence interval. Which of the following statements is most correct? A. The za/2 (found from R) used to calculate the 92% confidence interval is 1.750686. B. The za/2 (found from R) used to calculate the 92% confidence interval is 2.053749. C. The za/2 (found from R) used to calculate the 92% confidence interval is 1.405072. D. The za/2 (found from R) used to calculate the 92% confidence interval is 0.04. V2. A random sample of 16 students is taken from a larger normal population of students in a multi- lecture course and the sample mean (average) of their final grades is found to be 62.25. Suppose it is known that the sample standard deviation is 3.2. You wish to create a 96% confidence interval for the true population mean. Which of the following statements is most correct? a. The ta/2,n-1 (found from R) used to calculate the 96% confidence interval is 1.877739. b. The ta/2,n-1 (found from R) used to calculate the 96% confidence interval is 0.02. c. The ta/2,n-1 (found from R) that is needed to calculate the 96% confidence interval is 2.24854. O d. The ta/2,n-1 (found from R) used to calculate the 96% confidence interval is 2.60248. V3: A random sample of 100 students is taken from a larger population of students in a multi-lecture course and the sample mean (average) of their final grades is found to be 63.75. Suppose it is known that the population standard deviation is 3.9. You wish to determine whether the average grade for the population differs from 63.00. Use R to get the needed Z critical value and then create a 90% Z confidence interval for the average final grade for the population by hand. Choose the correct statement below. ) The test is not significant at the 10% significance level because 63.00 is inside the confidence interval you created. b) The test is not significant at the 10% significance level because 63.75 is inside the confidence interval you created. c) The test is significant at the 10% significance level because 63.00 is inside the confidence interval you created. d) The test is significant at the 10% significance level because 63.00 is outside the confidence interval you created