Question
Use the Heisenberg uncertainty principle to calculate Ax for an electron with AV = 0.170 m/s. 1.943x10^-4m = V me = 9.10939x10-31 kg h
Use the Heisenberg uncertainty principle to calculate Ax for an electron with AV = 0.170 m/s. 1.943x10^-4m = V me = 9.10939x10-31 kg h = 6.62608x10-34 Js = 3.14159265359... By what factor is the uncertainty of the (above) electron's position larger than the diameter of the hydrogen atom? (Assume the diameter of the hydrogen atom is 1.0010-8 cm.) Use the Heisenberg uncertainty principle to calculate Ax for a ball (mass = 172 g, diameter = 8.30 cm) with Av = 0.170 m/s. The uncertainty of the (above) ball's position is equal to what factor times the diameter of the ball?
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