Value Theorem may Pa 9. lim f(x) = 1 10. lim f(x) = f(0) x-+0 alue 1 11. lim f(x) = 2 x-2 x - 2 + 12. lim f(x) = 3 1 /( ) 13. lim f(x) does not exist. 14. lim f(x) = 3 x- 5 In Exercises 15-20, refer to the graph of the function fand determine whether each statement is true or false. 2v.0.2.0) 5.0 .2co.0) inunos ed no 3+ y=f (x ) 0 2 - 250ad.0 8ITO.0 omominos .2906 -3 -2 -1 2 3 4 5 er il .notlosaid To bodloc 15. lim f(x) = 2 16. limf(x) = 2 x - - x - 0 17. lim f(x) = 1 18. lim f(x) = 3 x-+ 2 x -> 4- -192 19. lim f(x) does not exist. 20. lim f(x) = 2 x -+ 4 + x - 4 In Exercises 21-38, find the indicated one-sided limit, if it exists 21. lim (2x + 4) 22. lim (3x - 4) x- 1+ x- 17 x - 3 y. li futucjion goes from 23. lim 24. lim x + 2axis. This is x- 2- x +2 x-it x + 1) mil asoct 25. lim ( navig or doidw *26. lim =av ard animated *-0" Mibait godw rodman*Post A . aboundnoozib .bollox - 1 Windtoo no1 (2)nonibaoox +1/ alsoibni 27. lim x- 0+ x 2+ 1 no 28. lim *- 2+ x2 - 2x + 3 29. lim Vx 30. lim 2Vx - 2 x - 0+ x - 2+ 31. lim (2x + V2 + x) 32. lim x(1 + V5+ x) * - - 5+ ore conti 1 + x 33. lim 1 + x x-1- 1 - x Justasiple 34. lim x-1+ 1 -1x w nisiqxa x )1 mil x2- 4 35. lim 36. lim Vx + 3 are must x-2 x - 2 x--3+ x4+1 progque 37. lim f(x) and lim f(x), where uor neo lafW . x-+0+ x-0 rem can be usce J2x if x 0In Exercises 39-44, determine the values of x, if any, at which each function is discontinuous. At each number where fis In Exercises 45-56, find the values of x for which each function is continuous. violated. discontinuous, state the condition(s) for continuity that are 45. f(x) = 2x2 + x- 1 39. f ( x ) = 2x - 4 ifx so 46. f(x) = x3 - 2x2 + x - 1 le dgung given Iqque soillo an if x > 0 47. f (x ) = - 2 C PIOS x 2 + 1 48. f(x) = 2 x2 +1 49. f(x ) = 2 50. f(x ) = x + 1 -5 2x - 1 x - 1 2x + 1 +-10 51. f(x) = 2 x 2 + x - 2 52. f (x ) = 2 x - 1 x 2 + 2x - 3 40. f (x ) = x2+ 1 ifx #0 if x = 1 10+ if x = 0 53 . f ( x ) = 1 2x - 1 ifx > 1 54 . f (x ) = { - 2x + 1 ifx 0 57 . f (x ) = 2 x x 2 - 1 58. f(x) (x - 1) (x - 2) -10 - 5 5 10 59. f ( x ) = -2 x 2 - 2x 60. f(x) =: x2 - 3x + 2 -5 x 2 - 3x + 2 *2 - 2x 61. THE POSTAGE FUNCTION The graph of the "postage function" for 2012, 42. f (x ) = 1x- 11 195 if0 0 discontinuous. Ay ( * ) -10-5 15 10 MMOD .80 -5. does 101 .000.5Se ei noizeimmoo no gai a 105 00012 s bing zi ord ,000.0018 buoyed 300 + Donut B es egrimes aid 44. x2 - 1 008 3+ if x # -1 f ( x) = 3x+1 200 if x = -1 ob er vaibomnoo nishso 100 + x (oz) 2 3 9 10 11 12 13