Question
Verify Property 2 of the definition of a probability density function over the given interval. f(x)=465x3, [2,3] Question content area bottom Part 1 What is
Verify Property 2 of the definition of a probability density function over the given interval.
f(x)=465x3,
[2,3]
Question content area bottom
Part 1
What is Property 2 of the definition of a probability density function?
A.
The area under the graph of f over the interval [a,b] is 1.
B.
The area under the graph of f over the interval [a,b] is b.
C.
The area under the graph of f over the interval [a,b] is a.
Part 2
Identify the formula for calculating the area under the graph of the function
y=f(x)
over the interval [a,b]. Choose the correct answer below.
A.Integral from a to b f left parenthesis x right parenthesis dx equals left bracket Upper F left parenthesis x right parenthesis right bracket Subscript a Superscript b Baseline equals Upper F left parenthesis b right parenthesis minus Upper F left parenthesis a right parenthesis
abf(x)dx=[F(x)]ba=F(b)F(a)
B.Integral from b to a f left parenthesis x right parenthesis dx equals left bracket Upper F left parenthesis x right parenthesis right bracket Subscript b Superscript a Baseline equals Upper F left parenthesis b right parenthesis minus Upper F left parenthesis a right parenthesis
baf(x)dx=[F(x)]ab=F(b)F(a)
C.Integral from b to a f left parenthesis x right parenthesis dx equals left bracket Upper F left parenthesis x right parenthesis right bracket Subscript b Superscript a Baseline equals Upper F left parenthesis a right parenthesis minus Upper F left parenthesis b right parenthesis
baf(x)dx=[F(x)]ab=F(a)F(b)
D.Integral from a to b f left parenthesis x right parenthesis dx equals left bracket Upper F left parenthesis x right parenthesis right bracket Subscript a Superscript b Baseline equals Upper F left parenthesis a right parenthesis minus Upper F left parenthesis b right parenthesis
abf(x)dx=[F(x)]ba=F(a)F(b)
Part 3
Substitute a, b, and f(x) into the left side of the formula from the previous step.
area | = | enter your response hereenter your response here465x3dx |
Part 4
Next, determine F(x). First, find the antiderivative of f.
465x3dx=enter your response here
Part 5
Let
C=0
in the expression obtained above and let the resulting expression be F(x). Evaluate the result over
[2,3]
using the far right side of the formula for the area.
area | = | enter your response hereenter your response here |
Part 6
area | = | enter your response here Simplify. |
Part 7
Is Property 2 of the definition of a probability density function over the given interval now verified? Choose the correct answer below.
A.
Property 2 of the definition of a probability density function over the given interval has been verified since the expression in the previous step equals b.
B.
Property 2 of the definition of a probability density function over the given interval has not been verified because the expression in the previous step does not equal the expected area value.
C.
Property 2 of the definition of a probability density function over the given interval has been verified since the expression in the previous step equals 1.
D.
Property 2 of the definition of a probability density function over the given interval has been verified since the expression in the previous step equals a.
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started