Very urgently

In an asenkron transmission a character size is 6 bits. When 2700 characters are transmitted, if total overhead amount is 9,45 Kbit, which answer is correct? O a. Stop Bit = 1 Parity = "Odd" Total Data Size = 27,90 Kbit O b. Stop Bit = 1,5 Parity = "Odd" Total Data Size = 25,65 Kbit O c. Stop Bit = 2 Parity = "Even" Total Data Size = 28,00 Kbit d. Stop Bit = 1,5 Parity = "No" Total Data Size = 22,10 Kbit O e. Stop Bit = 1 Parity = "No" Total Data Size = 19,20 Kbit For the above given signal each bit is separated by a vertical line. If duration of a bit is given as 48 ns, which answer is correct? O a. Data: 010100110111 Modulation Rate: 0,04 GBaud Encoding: Manchester O b. Data: 010100110111 Modulation Rate: 0,5 Kbaud Encoding: Manchester O c. Data: 011110101100 Modulation Rate: 0,02 Gbps Encoding: Manchester O d. Data: 011110101100 Data Rate: 0,25 Gbps Encoding: Differantial Manchester O e. Data: 111101011001 Modulation Rate: 0,04 Kbaud Encoding: Differantial Manchester In an asenkron transmission a character size is 6 bits. When 2700 characters are transmitted, if total overhead amount is 9,45 Kbit, which answer is correct? O a. Stop Bit = 1 Parity = "Odd" Total Data Size = 27,90 Kbit O b. Stop Bit = 1,5 Parity = "Odd" Total Data Size = 25,65 Kbit O c. Stop Bit = 2 Parity = "Even" Total Data Size = 28,00 Kbit d. Stop Bit = 1,5 Parity = "No" Total Data Size = 22,10 Kbit O e. Stop Bit = 1 Parity = "No" Total Data Size = 19,20 Kbit For the above given signal each bit is separated by a vertical line. If duration of a bit is given as 48 ns, which answer is correct? O a. Data: 010100110111 Modulation Rate: 0,04 GBaud Encoding: Manchester O b. Data: 010100110111 Modulation Rate: 0,5 Kbaud Encoding: Manchester O c. Data: 011110101100 Modulation Rate: 0,02 Gbps Encoding: Manchester O d. Data: 011110101100 Data Rate: 0,25 Gbps Encoding: Differantial Manchester O e. Data: 111101011001 Modulation Rate: 0,04 Kbaud Encoding: Differantial Manchester