VI. Projectile Motion A. An object released from ground level, y. = U m, at a velocity of 35 mfs at an angle of 30 above the +x direction. You are to determine the distance traveled horizontally using 3 different methods. Use g = 9.8 ma's2 when needed. a. Method one 1. ii. iii. Use the vertical component of the object's velocity and an appropriate equation to determine the time it will take for the object to reach it's peak height. The total time in the air will then be double the time to the peak. (Decide that this makes logical sense.) Use tm-r and horizontal component of the velocity and an appropriate equation to determine the distance traveled horizontally by the projectile. Method two 1. ii. Since v_._,r = 12,-,- {Make sure you know why this true), determine the total time taur using an appropriate equation. Use tair and horizontal component of the velocity and an appropriate equation to determine the distance traveled horizontally by the projectile. Method three 1. ii. Since y '=_v.- (Make sure you know why this true), determine the total time tau-l- using 15,,- and the position equation. Use tm and horizontal component of the velocity and an appropriate equation to determine the distance traveled horizontally by the projectile. B. Suppose a wall appears a certain distance from the release point of the projectile. Now the projectile hits the wall instead ofreaching the ground. a. Explain why methods 1 8L 2 are no longer valid options for determining how far the wall is from the original position of the object. If the object strikes the wall at a height, y; = 6.2 m above the ground, determine the horizontal distance that the wall is from the original position ofthe object. If you think that there may be two possible answers, explain what they each would represent