Vodacom 4G 6:49 AM 66% MECN2013A-DefSupp-Question... 1 of 1 Reading time: 17h20 to 17h25 Working time: 17h25 to 17h50 Submission time: 17h50 to 17h55 End of assessment: 17h55 QUESTION 6 (15 marks) 1/2 1/2 Fdt G (VG)1 MECN2013A (Deferred/Supp) Figure 1: Slender bar acted on by impulse 13A course of this The figure shows a slender bar PQ (mass m kg, length / mythat is pinned to a massless roller at P. It is hanging vertically and has an initial horizontal velocity of its mass centre of (VG)1. An impulse [Fdt acts on the roller at time = 0, which results in the roller P having a velocity of (vp)2 m/s to the left. After the impulse, the slender bara plane, such that Q is located verticale The system conditions are: 1=1.3 m m = 12 kg IG = 1.69 kg.m This that is Wits revolves a around P and swings upwards in the vertical question outside of (a) Draw the relevant diagrams and formulate all of the course the solution of the problem. (Hint: this is an impulsm-energy problem.) (9 marks) (b) Assuming now that the rebound velocity of the roller is c opon for Any of this equations that would allow for (VP)2 is zero, determine the limiting initial velocity of the bar, (VG)1, that is required to cause the bar to just swing to the vertical position, where Q is directly above P. Also determine the magnitude of the impulse [Fdt and the angular velocity @2, and the velocity of the mass centre after the impulse has acted, (VG)2. questo (6 marks) [Total: 15 marks] Q A