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walker stands stationary equillibrium EF=ON & Tsin & + Tsin & -mg = 2T sino = mg 2T sin 13.2 = 61.7 (9.81) >T=1325.322N

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walker stands stationary equillibrium EF=ON & Tsin & + Tsin & -mg = 2T sino = mg 2T sin 13.2 = 61.7 (9.81) >T=1325.322N Consider four situations shown below with four identical boxes each with mass 1.0 kg. In each case there is a 10 N force applied to the box. Rank the magnitude of the normal force, FN, exerted by the surface on the box, from the least to the greatest value? FN1 refers to the normal force in situation 1, FN2 refers to the normal force in situation 2, etc. Image size: S M L Max 10 N 10 N 450 1 2 3 10 N 10 N 60 A tightrope is connected at each end to a vertical tree trunk at a height of 1.05 meter above the ground. The two trees are located a distance 4.97 meters apart. At the midpoint of the tightrope, a 1.85 meter tall tightrope walker stands stationary on the rope, causing the rope to sag at an angle of 0 = 13.2. The tightrope walker has a mass of 61.7 kg and you can assume that the mass of the tightrope is negligible. Find the tension in the tightrope. [Warning: this problem may contain more information than is necessary to answer the question.] 0 0 Image size: S M L Max

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