Water flows through the pipe contraction shown in the figure below. For the given $0\mathrm{.}2-m$

difference in manometer level, determine the flowrate as a function of the diameter of the

small pipe, D$.$

Hint:

Apply hydrostatics to determine p$1$ and

p$2,$ hence $($p$1-$p$2)$

Apply Bernoulli's equation between

points $1$ and $2$ to determine $v2.$ Note that $z1=z2$

and $v1=0.$

Find the volumetric flowrate in $\frac{m^3}{s}$

using $Q=A2**v2$