Water is leaking out of a conical tank with pointed end down at the rate of 10 fts/min. The tank is H = 12 feet high and the radius of the circular opening is R = 4 feet. At what rate is the radius of the water surface changing when the water is d = 8 feet deep? You may use the formula V = col : Enter your exact answer in fu/min in the equation editor below. Click on E to launch the equation editor