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We are given with a memory which is byte addressable and the size of the memoryis 8 GBandalso size of the byte which is addressable

We are given with a memory which is byte addressable and the size of the memoryis8GBandalso size of the byte which is addressable is 4 byte or we can say that the memoryis4Byteaddressable. Now, consider the same memory device with K bit logical address anda2KBpagesize and the page table entries are 4 BYTE each. Assume the memory is againByteaddressable.Calculate:
a. Number of address bits(bits). b. Number of entries in the page table(pages).(divide your answer by 2^(19) andreportyourfinalanswer. c. Size of the page table (MB).

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