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We compute .c = 0.9001. Therefore, R2 =- 0 . 900 12 - 0 . a 102. We compare this with the computer-generated results for

We compute ".c = 0.9001. Therefore, R2 =- 0 . 900 12 - 0 . a 102. We compare this with the computer-generated results for the linear model to conclude that the exponential model, Model 2, is better since 08102 > 0.7936

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