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We find that ZnO dissolves to a concentration of 10 -3 M at a pH of 12, by the following reaction: ZnO + H 2
We find that ZnO dissolves to a concentration of 10-3M at a pH of 12, by the following reaction:
ZnO + H2O + 2OH- = Zn(OH)42-
What is the Gibbs free energy change for this reaction? Where would this equilibrium line plot on the Zn Pourbaix diagram?
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