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We have two divide-&-conquer algorithms, let's call them A and B, where A calls B. Their time complexities, () and (), are expressed by the

We have two divide-&-conquer algorithms, let's call them A and B, where A calls B. Their time complexities, () and (), are expressed by the following recurrence relations () = 4(/2) + () + () () = 6(/3) + (2log)

a. () = (2log2)

b. () = (2log3)

c. () = (2log2)

d. A() = (2log)

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