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We have two divide-&-conquer algorithms, let's call them A and B, where A calls B. Their time complexities, () and (), are expressed by the
We have two divide-&-conquer algorithms, let's call them A and B, where A calls B. Their time complexities, () and (), are expressed by the following recurrence relations () = 4(/2) + () + () () = 6(/3) + (2log)
a. () = (2log2)
b. () = (2log3)
c. () = (2log2)
d. A() = (2log)
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