We opened 20 bags M&Ms to find the average number of different colors in each bag.

Number of total M&Ms 1139

Number ofblue 237P^= .21

Number of green 188P^= .16

Number of Red 128P^= .11

Number of Brown 163P^= .14

Number of Yellow 172P^= .15

Number of Orange 251P^= .22

Average number 0f total M&M's in a bag: 56.95

Standard Deviation: 1.47

5 number Summary MIn- 55Q1- 56 M- 57Q3-58 MAX- 60

IQR= 52

In2008 the Mars company listed on their website the following distributions of colors of M&Ms

24% blue, 20% orange, 16% green, 14% yellow, 13% red, 13% brown think of these proportions as parameter values for each color

Several market research articles have calculated the average number of M&Ms in a day to be 56. M&Ms enthusiast around the world have begun to express concern that there are less than 56 candies in the bag. Use sample statistics from the above to contact hypothesis test to determine if there is a valid concern. Before we conduct a test answer a few questions.

How do we find 95% bootstrap confidence interval for total number of M&M's ?

How are a bootstrap sample and a boot strap distribution created?