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We proved that TQBF is PSPACE - complete. We can use this to give a second proof that PSPACE = NPSPACE, by proving that TQBF
We proved that TQBF is PSPACEcomplete. We can use this to give a second proof
that PSPACE NPSPACE, by proving that TQBF is also a NPSPACE complete
problem. For this problem, do not assume PSPACE NPSPACE by Savitch's
theorem, as that is what we are trying to prove, you may only assume PSPACE sube
NPSPACE.
a points Prove that TQBFin NPSPACE Hint you should not be able to show
that TQBFinNP
b points We proved that AALin PSPACE that Explain how you
could modify the proof we did to show that AALin NPSPACE that
Hint why could we show SAT complete for a nondeterministic class, and TQBF
complete for a deterministic one?
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