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We proved that TQBF is PSPACE - complete. We can use this to give a second proof that PSPACE = NPSPACE, by proving that TQBF

We proved that TQBF is PSPACE-complete. We can use this to give a second proof
that PSPACE = NPSPACE, by proving that TQBF is also a NPSPACE complete
problem. For this problem, do not assume PSPACE = NPSPACE by Savitch's
theorem, as that is what we are trying to prove, you may only assume PSPACE sube
NPSPACE.
(a)(5 points) Prove that TQBFin NPSPACE (Hint, you should not be able to show
that TQBFinNP ).
(b)(5 points) We proved that AALin PSPACE that L?pTQBF. Explain how you
could modify the proof we did to show that AALin NPSPACE that L?pTQBF
(Hint, why could we show SAT complete for a nondeterministic class, and TQBF
complete for a deterministic one?)
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