We want to compute the integral / (4x +4x+6) e5x dx using two (and only two) integration by parts. This means that you have to make a good choice of f and g' for your two integration by parts. For the first intagration by parts, you should choose [f(x), g'(x)] = Warning: for this question, you must use strict calculator notations and also include the square brackets in your answer; in particular, you must use * for every multipliaction (e.g. 2x is written 2*x.) to get /(4x2 4x + 4x + 6) e5x dx = G(x) H(x)dx, where G(x) = 44 and H(x) = Now, to integrate [f(x), g'(x)] = B [ H(r)da, we need to use the method of integration by parts a second time with Warning: for this question, you must use strict calculator notations and also include the square brackets in your answer; in particular, you must use * for every multipliaction (e.g. 2x is written 2*x.) to get H(r)dr = +C (Don't add the constant of integration C since we have done it for you.) We have then found that /(4x + +4x+6)e5xdx = +C