We want to compute the limit below with I'Hospital's Rule lim cot(5x) sin(x) x-+0 a) What is the indeterminate type of this limit? 0 00 - 00 0 0 0 * 00 0 10 0 % b) To be able to use I'Hospital's Rule, we rewrite the limits in terms of cosine and sine functions only, to get lim cot(5x) sin(x) = lim A(a) x-+0 x->0 B(x) where [ A(x), B(x)] = FORMATTING: Enter your answer as [ A(a), B(a)], including the square brackets and with a comma (,) between the terms. For this question, you must use strict scientific calculator notation: multiplication is written * ; for example, you must write 3 sin (3x) as 3*sin(3*x). c) What is the indeterminate type of the limit lim A(2C) found in (b)? x-0 B(x) 0 0 * 00 0 0 0 00 - 00 0 d) According to I'Hospital's Rule, lim A(a) lim A1 (2) x->0 B(x) x-0 B1(x) for [ A1 (2), B1 (20)] = FORMATTING: Type your answer in the form [A] (), Bj ()], include the square brackets and write a comma between A] (2 ) and By (a). For this question, you must use strict scientific calculator notation: multiplication is written * ; for example, you must write 3 sin(3x) as 3*sin(3*x). e) Conclude that A1 (a) lim cot(5x) sin(x) = lim x-0 x-0 Bj(x) FORMATTING: Give the exact answer.Consider the limit lim 2-700 (xe5 / x - x a) What type of indeterminate form is this? 0 0 0 090 0 00/00 0 00 - 00 0 010 0 0.00 b) Compute the limit, using I'Hospital's Rule in the appropriate manner, if it applies. lim xe 5/ x - 20 =